5500=2x^2+10x

Solution for 5500=2x^2+10x equation:

5500=2x^2+10x

We move all terms to the left:

5500-(2x^2+10x)=0

We get rid of parentheses

-2x^2-10x+5500=0

a = -2; b = -10; c = +5500;
Δ = b2-4ac
Δ = -102-4·(-2)·5500
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-210}{2*-2}=\frac{-200}{-4}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+210}{2*-2}=\frac{220}{-4}
=-55
$